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X^2-26X=-25
We move all terms to the left:
X^2-26X-(-25)=0
We add all the numbers together, and all the variables
X^2-26X+25=0
a = 1; b = -26; c = +25;
Δ = b2-4ac
Δ = -262-4·1·25
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-24}{2*1}=\frac{2}{2} =1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+24}{2*1}=\frac{50}{2} =25 $
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